Hi,
I’d like to open different Xpages from a button on a Custom Control, based on the current URL.
On the onClick event of the button I selected “Open Page” then I added the following script to the “Name of Page to Open”:
var str = context.getUrl();
var xpg = “xpages1.xsp”;
if (str.indexOf(xpg) > 1) {“xpages2.xsp”}
else {“xpages3.xsp”}
The selected language is “JavaScript (server side)”
I just can’t get it work…
Thank you for your help,
Etyien
Subject: Convert the url to a string type
As far as I remember reading, in 8.5 getUrl would return a string but this was actually incorrect and it should have returned an object of a class. They have since fixed this in 8.5.1+.
If you wrap your str variable in @Text or use toString (if you don;t want to use @Formula) that should fix it for you.
var str = @Text(context.getUrl());
var xpg = “xpages1.xsp”;
if (str.indexOf(xpg) > 1) {“xpages2.xsp”}
else {“xpages3.xsp”}